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I'm using an Arduino (Nano 33 IoT) board for a project and apparently this board can only supply with 3.3 volts when a 9V battery is connected to it through Vin and GND pins. In other words, I'm powering the Arduino board with a 9V battery, but I want to power supply an LCD display through my Arduino, but I can't.

This Arduino board only has a 3.3 volts pin. It has a 5V pin but it's only enabled when the Arduino is powered by USB.

The problem: The LCD display only takes up to 5.5V, and its minimum required voltage is 4.5V. I cannot power it from the Arduino board because voltage is too low, and I cannot power it directly from the 9V battery because it's too high.

What can be done?

Note: I don't have a voltage regulator to use between the LCD and battery.

Is it possible to use voltage divider?

Note: The LCD screen that I'm using is connected to I2C protocol module. It has only 4 pins: SCL and SDA pins (connected to arduino), and 2 power pins (GND and VCC).

it should look like this when connected to a regular arduino uno: Figure 1: Arduino UNO with I2C LCD displaay

What would the circuit look like if I desire to use voltage divider?

Or can I simply use just one resistor between the 9V battery positive pin and the LCD's positive power pin?

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